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16x^2+80x+64=0
a = 16; b = 80; c = +64;
Δ = b2-4ac
Δ = 802-4·16·64
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-48}{2*16}=\frac{-128}{32} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+48}{2*16}=\frac{-32}{32} =-1 $
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